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  1. JBRULES
  2. JBRULES-1040

Multi-pattern accumulate support

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      [Edson said there might be already such an issue, but I couldn't find it looking through jira.]

      Something like this should be possible:

      $multipleQueensHorizontal : Long()
      from accumulate(
      $q1 : Queen($id : id, $y : y);
      Queen(id > $id, y == $y);
      , count($q1)
      );

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                • Assignee:
                  tirelli Edson Tirelli
                  Reporter:
                  ge0ffrey Geoffrey De Smet
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